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22 Jul 2010, 12:44 (Ref:2730608) | #1 | ||
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Can anbody give me a good answer?
I am having a discussion (we shall call it that for now) on another forum regarding power to weight ratio.
I say 2 identical cars both with the same gearing and power say 500BHP but have a different weight, one has been stripped out, and lets say one car weighs 1500kilo and one car weighs 2000kilo Given a long enough straight road the lighter car will have a greater top end than the heavier car due to it's power to weight ratio. The lighter car will have 333BHP per ton. The heavier car will have 250BHP per ton Am I wrong? |
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22 Jul 2010, 12:48 (Ref:2730611) | #2 | ||
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I would have thought that the reduced weight would improve acceleration (disregarding any traction issues) but think that overall top speed wouldn't be affected as this is more of a power to aerodynamics equation, and not weight.
(Obviously, improved acceleration would allow you to reach this top speed earlier, or for you to achieve a higher top speed on a shorter straight). |
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22 Jul 2010, 12:54 (Ref:2730614) | #3 | |
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The lighter car would be faster but not for the reasons given. Terminal velocity is when the cars power becomes equal to the drag (as you go faster aerodynamic drag increases and equals the force of the engine)
BUT on this race the heavier car would have more rolling resistance and therefore when added to the aero load ( the same for both ) you get a higher backward force. you could of course say that the heavier car would be sitting lower on it suspension and would therefore have les drag under the car but i believe that this would be going a tad to far. Hope this Helps, David |
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22 Jul 2010, 12:54 (Ref:2730615) | #4 | ||
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It all depends on gearing. Given identical gearing, if both cars can rev right up to the rev limiter in top gear, then the lighter car will be no faster; if that's not the case, then the lighter car may be marginally faster, but I suspect the difference would be minimal, as the only effect the lighter weight would have at steady speeds would be to slightly reduce rolling resistance because the tyres are carrying less weight.
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22 Jul 2010, 13:46 (Ref:2730636) | #5 | ||
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I am getting the feeling I am going to be prooved wrong here
But assuming the power does not outreach the gearing, I would of thought the lighter car would have more top speed Isn't this prooved when a fast car that is aerodynamic then fits a spoiler to create down force reduces it's top speed due to drag etc? |
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22 Jul 2010, 19:51 (Ref:2730799) | #6 | |
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Given that the gearing, frontal area and CD factor allow for a top speed of, say, 150mph plus, the top speeds of both cars will be more or less the same - within 2mph I would say.
The higher the top speed attained, the lesser the difference will be between the two cars, as a higher percentage of the engine power is 'lost' to aero drag. Say the top speed attained by the lighter car is 180 mph, then the power lost to drag will be just under 400bhp! The heavier car would achieve 178.5mph with only (ONLY!) 389bhp lost to drag, but the same total of 500bhp 'consumed'. Of course the car with the better power/weight ratio will accelerate more quickly (subject to traction grip being sufficient) and therefore achieve 'terminal velocity' in a quicker time/shorter distance. Last edited by phoenix; 22 Jul 2010 at 19:59. |
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23 Jul 2010, 09:02 (Ref:2731039) | #7 | |||
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I think that proves the point against you. If on adding the spoiler, the same weight as the spoiler was taken out of the car, would it still have the same top speed? No. It weighs the same but has more drag >> less top speed. Top speed depends on power, not weight (excepting the suspension height, rolling resistance etc.) John |
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23 Jul 2010, 14:07 (Ref:2731184) | #8 | ||
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Unfortunately its not a sliding scale. The top speed of a F1 car with 800 + hp is something like 230mph. Whereas a purpose built car with the same power to weight would probably be able to do at least 100 mph more.
It is all down to drag at the end of the day . |
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23 Jul 2010, 15:56 (Ref:2731244) | #9 | ||
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They had a vertical fin in place of the rear wing and a lower downforce front wing than used in racing, but of course there would still be a lot of drag from the open wheel configuration. |
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23 Jul 2010, 17:43 (Ref:2731321) | #10 | ||
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Yes but it had to be modded to do it . Adrian Newey (who I have raced against) told me that an F1 car in race set up can only pull about 230 mph.
The point I was trying to make was that power vs speed isn't linear as you need a damned sight more the faster you go. I'm not going to google around pretending I know the facts regards power vs mph , But of course you know that |
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Balls of steel (knob of butter) They're Asking For Larkins. ( Proper beer) not you're Eurofizz crap. Hace más calor en España. Me han conocido a hablar un montón cojones! Send any cheques and cash to PO box 1 Lagos Nigeria Africa ! |
23 Jul 2010, 18:11 (Ref:2731339) | #11 | ||
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I'm so sad I didn't have to google it :-( |
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23 Jul 2010, 21:13 (Ref:2731453) | #12 | ||
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26 Jul 2010, 19:25 (Ref:2733567) | #13 | ||
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I imagine that the problem is about with power vs. weight of a rolling vehicle, and therefore what difference that makes on a potential top speed. We must therefore reduce away all extraneous factors so that we only have to do with the issue of factors involved. Air resistance is the major factor, then we have rolling resistance. We can think of two identical cars in terms of air resistance and it is tricky with how weight affects the rolling resistance in terms of a practical experiment. In any case, since rolling resistance is a minor factor so it will not differ much at top speed with a weight difference of 25%. But the lighter car will go a little bit faster.
(As fare as I understandable) Goran |
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6 Aug 2010, 02:47 (Ref:2740168) | #14 | ||
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Thanks for everyones help on this........And I do understand the theory perfectly and agree....but.....I know from my experience driving minis....if you have your foot on the floor you will do 90mph all day long.....If you have the same mini with 4 up you will be lucky to get 75-80mph all day long so how does the original theory hold up in that circumstance?
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6 Aug 2010, 08:28 (Ref:2740245) | #15 | |||
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6 Aug 2010, 09:45 (Ref:2740283) | #16 | ||
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For the cars mentioned in the OP The aero drag at 90mph is a quarter of the drag at 180mph At a steady 180mph, 80% of the power is consumed by drag and 20% by moving 'the load' At a steady 90 mph 50% of the power is lost to aero and 50% to the load At a steady 75 mph 34% of the power is lost to aero and 66% to the load So, with a smaller engine the same applies. With four up in a mini at 75 mph about 66% of the power is used to overcome the load, leaving only 34% to overcome aero drag - hence the lower top speed (except downhill where more power is available to overcome the aero as less, thanks to gravity, is being used to carry the load) Last edited by phoenix; 6 Aug 2010 at 09:54. |
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12 Aug 2010, 11:35 (Ref:2743457) | #17 | |||
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Or something. |
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12 Aug 2010, 13:00 (Ref:2743521) | #18 | ||
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Close, but not exactly right! Everything else being equal, for a given accelerative force, higher mass just means slower acceleration.
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12 Aug 2010, 15:44 (Ref:2743605) | #19 | ||
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Rolling resistance - heavier load the tyres are more compressed.
You could experiment with higher inflation pressures! I suspect that you would need very hard tyres indeed to ensure that the contact patch was the same size under load. John |
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12 Aug 2010, 16:06 (Ref:2743612) | #20 | ||
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16 Aug 2010, 08:26 (Ref:2745072) | #21 | |||
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My point was that all else isn't equal - as the aero resistance (and rolling resistance) has increased to a point where you don't have enough power to accelerate at all. Since your mass is higher is a heavier car, you actually need more force to accelerate it, that force cannot be provided by the power as all the power is going towards overcoming rolling and wind resistance. Remove some weight, and your power requirements to accelerate become lower, get below the air and RR threshhold, so you can accelerate slightly. |
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Locost #54 Boldly Leaping where no car has gone before. And then being T-boned. Damn. Survivor of the 2008 2CV 24h!! 2 engines, one accident, 76mph and rain. |
16 Aug 2010, 09:15 (Ref:2745088) | #22 | ||
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16 Aug 2010, 20:34 (Ref:2745448) | #23 | ||
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James, Dave
Dave is quoting Newton's Second Law, which says (not in Newton's words) that "acceleration is produced when a force acts on a mass. The greater the mass (of the object being accelerated) the greater the amount of force needed (to accelerate the object)". And vice versa, the greater the force, the greater the acceleration. In Dave's universe, the only thing that stops an object, however big, accelerating in response to a force, however small, is Special Relativity, that Newton wot not of. Einstein said that nothing can go faster than light, and that mass increases as light speed is approached so that acceleration from a constant force slows. In yours, James, drag increases as the square of speed, so acceleration diminishes to a very small increment as maximum power (force) is approached. He is ignoring drag, rolling resistance, frontal area, downforce and the colour of the driver's fly-buttons, and as such he is right on Earth, in space or on Gallifrey. You are ignoring a fundamental Law of Physics. The two of you are arguing that oranges are apples, so stop it! John |
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17 Aug 2010, 10:48 (Ref:2745826) | #24 | |
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I found this site, which has some useful answers:
http://www.cameronsoftware.com/ev/EV...MotorSize.html I tried "The drive power spreadsheet" link at the bottom and it works too. |
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17 Aug 2010, 16:13 (Ref:2746049) | #25 | |||
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That site is for ELECTRIC motor cars! But I suppose the same rules apply! J |
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