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6 Dec 2004, 05:57 (Ref:1171990) | #26 | |||
Rookie
Join Date: Jun 2004
Posts: 40
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Quote:
can you imagine other way to pull 2.6 G of lateral load than to produce huge downforce? My calculations are verry simple: M x A = Fv x n M= total weight of the car , let say 1250 kg A= lateral acceleration , this is 2,6G Fv= vertical load /weight+downforce/ n= friction coefficient of the tyres, let say n=1,4 than Fv=(MxA)/n=(1250x2,6)/1,4 Fv=2321 kg so the downforce= 2321-1250=1071 kg so we need to generate ower 1000 kg of downforce to produce so much lateral load and sticky tyres. I know that is very simple model but in general it should be OK. If I make a mistake or I´m wrong please let me know! |
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6 Dec 2004, 10:00 (Ref:1172114) | #27 | ||
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Racer
Join Date: Mar 2004
Posts: 319
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Lemanfan,
Looks ok as a brief calculation. However, n is not a constant and get less by raising load. It may fall off by 5% from weight transfer allready at 1g of corninring, depending on CGH. When it comes to these numbers of downforce Iwould imagine n to become 15% less. So we need even more downforce for the stipulated 2,6g. If no downforce is used we will rely on rubber quality and size, track surface and eaven loading of the total rubber area in contact with the road. Less weight per area of footprint will raise n, and the cornering force gets greater. Therfore wide tires, wide track width, low CGH is the only key appart from rubber quality and pavement. We are pretty much limited to say 1,5g then. Goran Malmberg |
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6 Dec 2004, 11:57 (Ref:1172150) | #28 | |||
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Join Date: Jun 2004
Posts: 40
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Quote:
Goran, You right I just made a very simple calculation to find out the downforce levels It is not so simple there is a lot of other factors just like you said. This calculation does not include weight transfer. We need even more downforce to pull 2,6 of lateral G. I just want to say that car which can corner at 2,6 g must produce much more downforce than we expect from such a car. I agree with Mike about the downforce levels of Saleen "but 2,6G seems to don´t agree whith it". |
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6 Dec 2004, 13:06 (Ref:1172236) | #29 | |||
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Join Date: Mar 2004
Posts: 319
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Quote:
Load transfer raise the load on the outside tires, therby reducing N. But even the aero-downforce raises the load on ALL 4 tires. This means that if we at 1250kg static weight load got n=1,4, we may at 2,6g and 2321 kg load have only n= 1,2 as the load has icreased on all tires. This was beside of load transfer, then even load transfer comes in to picture. But I agree whith you, a lot thingas allways come in to the picture. I just wanted to point out that if we should susspect the car to corner 2,6g on a continious basis, we need A LOT downforce. Kind regards Goran Malmberg |
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6 Dec 2004, 13:14 (Ref:1172252) | #30 | ||
Racer
Join Date: May 2004
Posts: 376
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Hm .the saleen runs quite a bit lower than 3 inches at the front ,i suppose...and has quite a bit of frontoverhang.
But in the end I believe the figures result of the car being compressed into the dip andrunning very close to the ground when changing direction and so the big number apears in the data log ..it is not really representing the cars capability it shows the stress going into the car in that dip. |
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6 Dec 2004, 13:29 (Ref:1172270) | #31 | |||
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Join Date: Jun 2004
Posts: 40
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Quote:
I was taking the tyre with friction coef. of 1,8 at zero vertical load which will drop by 0,065 on every 100kg of vertical load. After adding weight and downforce we will get around n=1,4. |
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